Path 06 · Module 05

Propagation, Channels & Link Distributions

A link does not have one received power for every place and orientation. Follow the power, choose the channel model, and ask what the lower tail can actually support.

Before you begin

Bring Modules 06.1–06.4, especially realized gain and polarization and arrays and diversity, plus Path 01 fields and noise. The RF Systems lessons on requirements and sensitivity are recommended; the receiver screen needed here is supplied explicitly.

By the end, build an auditable link ledger; distinguish coherent geometry from statistical variation; calculate a received-power/SINR distribution; and state its population, percentile, model domain and missing evidence. Full terrain/ray tracing, channel-sounding execution, protocol receiver rules, detailed measurement and legal operation remain outside this lesson.

01 / 10

Failure: free-space path loss becomes a guaranteed range

The spreadsheet says 100 m. Which 100 m does it mean?

Our illustrative engineering case is the small 2.45 GHz telemetry node and its gateway. It works across an empty outdoor path. On a metal machine, the same separation sometimes fails; down an office corridor, turning the node changes the result. A nearby transmitter makes the failures more frequent. The original spreadsheet contained free-space loss and one receiver threshold.

The calculation may be correct for its inputs. The claim becomes wrong when one geometric reference is promoted into a product guarantee. A real link includes antennas in particular directions and mounting states, obstructed or reflected paths, interference, receiver behavior, and a population of places and times.

Think about itA median signal is above the receiver threshold. Must 95% of the links work?
Answer

No. The median describes the middle of the assumed population. In our office fixture, median SINR is 15.648006 dB against an 8 dB requirement, yet 6.305774% of the modeled received powers fall below the threshold. A favorable center can coexist with an unacceptable lower tail.

Repair the range claim before changing transmit power
Missing conditionWhy it changes the decision
Antenna stateFrequency, direction, realized gain, polarization, body and mounting change spatial coupling.
Environment and geometryLOS, ground, edges, doors, material layers and multipath determine whether the selected model applies.
Receiver and interfererSame-band noise/interference and a named quality criterion determine the threshold.
Population and evidenceDistance alone names neither positions/times/orientations nor the fraction to be served, correlation, confidence or uncertainty.
Common misconceptionFree-space loss is a guaranteed product range.

It is a conditional propagation reference. Even a perfectly computed threshold crossing cannot validate an unobserved environment or antenna state. Retain the missing evidence as unknown.

The first repair is bookkeeping: write down exactly where the power is known and how it reaches the receiver.

03 / 10

Friis and free-space basic transmission loss

How much of a spreading wave can a receiver collect?

In unobstructed far-field free space, the power flux from a fixed directional EIRP spreads over area proportional to r². A matched, aligned receiver collects flux through its effective aperture. Combining S = PₜGₜ/(4πr²) with Aₑ = Gᵣλ²/(4π) gives the familiar transmission equation. The gain and matching convention must stay consistent with the power planes.

Pr=PtGtGr(λ4πr)2LFS=20log10(4πrfc)\begin{aligned}P_{r} &= P_{t} G_{t} G_{r} (\frac{\lambda }{4\pi r})^{2} \\ L_{\mathrm{FS}} &= 20 \log _{10}(\frac{4\pi r f}{c})\end{aligned}Linear watts and dimensionless gains; LOS, far field, polarization alignment and compatible matching. Use λ=c/f with exact c=299792458 m/s.

ITU-R P.525-5, Annex §2.3 defines free-space basic transmission loss between isotropic antennas. That loss is a ratio in dB; it is not the complete receive level. The ledger supplies conducted power, gains and the remaining losses separately.

Independent free-space anchors · 2.450 GHz · geometric baseline, not measured
Distance rLFS · dBFull default state-A R1-RX power
1 m40.231104909Algebra −31.938067181 dBm; suppressed by the default 2 m far-field screen
10 m60.231104909−51.938067181 dBm under LOS and aligned-gain assumptions
100 m80.231104909−71.938067181 dBm under the same assumptions
Think about itKeep both gains fixed. Multiply distance by ten. How much power remains?
Answer

The loss rises 20 dB; receive power becomes one hundredth. Doubling distance instead adds 20 log10(2)=6.020600 dB. Frequency is unchanged; this is geometric scaling under fixed antenna conditions.

Go deeperThe MHz/km constant and a conservative domain screen

With f in MHz and r in km, the exact-c constant is 20 log10(4π·10⁹/c) = 32.447783222 dB. P.525’s familiar rounded form uses 32.4. This workbench calculates from SI and rounds only for display.

For each ray, require r ≥ max(2Dtx²/λ, 2Drx²/λ, 10Dtx, 10Drx, 10λ). Dtx=0.10 m and Drx=0.20 m give a 2 m minimum here. This composite screen is a deliberately conservative lesson assumption, not a universal IEEE boundary or proof of quiet-zone accuracy. A failed screen suppresses receive-power and reliability conclusions; passing it does not establish clear LOS or a calibrated model.

Common misconceptionFree-space basic loss directly states the received power.

It omits the transmitter level, both antennas and their operating conditions. A loss of 80.231105 dB says nothing by itself about which receiver threshold will be met.

The λ² factor also raises a subtle question: what is being held fixed when frequency changes?

04 / 10

Frequency dependence is not one slogan

Does “higher frequency loses more” describe propagation, or the antennas you chose?

At fixed gain, Friis receive power scales as f⁻². But gain is a relationship to an isotropic reference, not a fixed collection area. For an electrically large aperture with constant physical area A and aperture efficiency ηₐ, G = 4πηₐA/λ². Raising frequency increases its ideal gain while narrowing its beam.

Double frequency, same distance and conducted power · ideal LOS comparison
Antenna constraintGain changeReceive-power change
Both supplied gains fixed0 dB on both ends−6.020600 dB; power × 1/4
One fixed physical aperture, other gain fixed+6.020600 dB at the aperture0 dB; ideal cancellation
Both physical apertures fixed+6.020600 dB at each end+6.020600 dB; power × 4

These comparisons assume electrically large efficient apertures, aligned pointing, compatible polarization and match, and far-field validity at both frequencies. The far-field distance itself can increase as wavelength falls. An arbitrary small printed antenna does not inherit this aperture scaling; its current distribution and efficiency may change instead.

Common misconceptionHigher frequency always gives less received power, regardless of the antenna constraint.

The three rows describe different engineering experiments. The workbench frequency control performs only the fixed-supplied-gain comparison; it never invents a larger gain or a new antenna response.

Real media add further frequency dependence. ITU-R P.676-13, Scope and Annex 1 §1 models dry-air and water-vapour attenuation using atmospheric conditions and spectral lines. Matching, polarization, material properties, path length and weather all matter. A frequency dial alone supplies none of those conditions.

Go deeperAbsorption is distinct from geometric spreading

P.676-13’s line-by-line method uses pressure, temperature and water vapour; its stated scope extends to 1000 GHz. The recommendation is a model route here, not an added scalar loss. The workbench implements no gas or rain correction. Absence of such a row means the effect is outside the modeled scenario, not that measured atmospheric attenuation is zero.

Before adding a generic “wall loss,” identify which physical mechanisms are present and which model could represent them.

05 / 10

Reflection, diffraction, scattering, penetration, and clutter

A steel cabinet blocks the direct path. Where can the received field come from?

Energy may reach the gateway by reflection from a wall, diffraction around an edge, scattering from rough or small objects, or transmission through surrounding material. These mechanisms alter phase, delay, angular structure and polarization as well as average power. An obstruction can create another useful path while also weakening the original one.

Mechanism → model route → evidence required · no generic wall coefficients
MechanismModel / source routeWhat must be known
Specular reflectionCoherent geometry and boundary model; two-ray is the bounded example below.Surface geometry, incidence, complex permittivity, polarization and roughness relative to wavelength.
Diffraction around edgesITU-R P.526-16 (11/2025)Path profile, obstacle geometry and clearance; select the applicable diffraction case.
ScatteringResolved paths or a justified statistical channel; Tse & Viswanath §2.1.7.Size/roughness, angle/polarization distribution and unresolved-path population.
Penetration / building materialsRoute through P.2040 / P.2109 in the P-series index.Material and layers, moisture, thickness, incidence and whether loss means one wall or building entry.
Indoor path statisticsITU-R P.1238-13 (09/2025)Applicable building/path category, frequency, geometry, statistic and calibration population.
Vegetation / clutterP.833 vegetation; P.2108-1 (09/2021) clutter.Vegetation depth/state and water content; clutter geometry and model-specific terminal conditions.
Gas / rainP.676-13; P.838-3 (03/2005).Atmosphere and path integration; rain rate/polarization and a complete applicable prediction method.

The P-series catalogue was checked on 7 September 2026. Those entries establish routing and current identity. Only P.525’s point-to-point formula and P.676’s stated scope/introduction were read here as recommendation text; no unseen material table or indoor coefficient is imported.

Think about itCan you add a wall penalty to an empirical indoor model without further checking?
Answer

Only if the empirical model’s definition excludes that wall contribution. A model fitted across obstructed paths may already include it statistically. Adding it again can double count loss; treating it as independent can also invent a probability distribution.

Common misconceptionPath loss belongs to transmitter frequency alone.

Geometry, environment and the chosen loss definition are equally necessary. “At 2.45 GHz” does not identify a corridor, the terminal heights, a material stack or a population.

One coherent reflected path is enough to show why even the free-space baseline is not a pointwise lower-loss bound.

06 / 10

Two-ray interference creates distance-dependent nulls

Can moving farther from the node improve a link?

Two paths carry copies of the same narrowband signal. Their phases can reinforce or oppose. As horizontal range R changes, the direct and reflected lengths change by different amounts. A receiver can move out of a cancellation region even while geometric spreading increases.

rd=R2+(hthr)2rr=R2+(ht+hr)2Δr=4hthrrr+rd\begin{aligned}r_{d} &= \sqrt{R^{2} + (h_{t}-h_{r})^{2}} \\ r_{r} &= \sqrt{R^{2} + (h_{t}+h_{r})^{2}} \\ \Delta r &= \frac{4h_{t}h_{r}}{r_{r} + r_{d}}\end{aligned}Flat ground; positive R, ht and hr in metres. k=2π/λ. The stable Δr formula avoids subtracting nearly equal lengths.
H=(λ4π)[1rd+ΓgroundejkΔrrr]PLtworay=10log10H2\begin{aligned}H &= (\frac{\lambda }{4\pi })[\frac{1}{r_{d}} + \frac{\Gamma _{\mathrm{ground}}e^{-jk\Delta r}}{r_{r}}] \\ \mathrm{PL}_{\mathrm{two-ray}} &= -10 \log _{10}|H|^{2}\end{aligned}e^(+jωt); the common direct-path phase has unit magnitude and is removed. Γground is a supplied complex field-reflection proxy, including the chosen polarization convention.

Replace the ledger’s entire path term with this result. Do not also subtract free-space loss. This simplified pair shares the same supplied antenna and polarization factors on both rays; angle-dependent vector patterns, roughness and multiple reflections are omitted. Each ray must pass the far-field screen.

Direct and reflected fields interfere over distanceThe schematic shows a node and gateway above a flat ground plane. The log-distance sweep compares coherent path loss to direct-path free space. Oscillatory peaks are destructive-interference nulls. Geometry is schematic, not to scale.ht 1 mhr 2 mdirect rdflat ground · Γ proxy407511021050100500Horizontal distance R · m · logarithmicPath loss dB · solid: two-ray · dashed: Friis at rd
Calculated at 2450 MHz; ht/hr = 1/2 m; Γ = 1180°. Both rays share supplied pattern/polarization factors. The sweep displays algebra over 2–500 m; points whose ray length is below 2.000000 m fail this lesson’s far-field screen. Selected R = 100 m: rd = 100.004999875 m, rr = 100.044989880 m, Δr = 0.039990005 m. No terrain, curvature or material solver.
Independent two-ray fixture · 2.450 GHz, ht=1 m, hr=2 m, Γ=−1
Horizontal RDirect path rdCoherent path lossDirect-path Friis loss
10 m10.049875621 m59.389182377 dB60.274318647 dB
20 m20.024984395 m60.965235911 dB66.262548635 dB
50 m50.009999000 m69.245047965 dB74.212241826 dB
100 m100.004999875 m75.567267219 dB80.231539182 dB
500 m500.000999999 m101.999529643 dB94.210522368 dB

At R=100 m, rd=100.004999875 m, rr=100.044989880 m and Δr=0.039990005 m. The coherent loss is 75.567267219 dB, less than the direct free-space value near 80.23 dB. Constructive interference raises power locally; it does not create energy or define a whole-space power balance.

Common misconceptionFree space is always the pointwise optimistic result.

Coherent multipath can produce enhancement or deep cancellation in a particular direction. A reflected field is not a separate uncorrelated power to add.

Go deeperWhen the inverse-fourth-power asymptote appears

For Γ≈−1, smooth flat ground, R much larger than both heights and kΔr≪1, Δr≈2hₜhᵣ/R and 1−e^(−jkΔr)≈jkΔr. Then |H|≈hₜhᵣ/R² and power scales approximately as R⁻⁴. These restrictions explain the asymptote; they do not replace the coherent curve at arbitrary distances. Tse & Viswanath, §2.1.5 and Exercise 2.5 develop the ground-plane mechanism.

Two exactly equal in-phase complex amplitudes give four times one-path power; equal opposite amplitudes give zero. Those are algebraic limiting cases. Positive-height geometry does not necessarily create an exact zero. With Γ=0 the model recovers Friis at rd, not horizontal R.

Geometry explains a particular point. A site with incomplete geometry often needs a different kind of statement: a distribution.

07 / 10

Path loss is often a distribution

What does “5 dB of variation” describe?

Imagine measuring local mean received powers across an agreed set of corridor positions. Their central trend may follow distance while obstructions create residual differences. A log-distance model expresses that trend in dB; Gaussian residuals in dB correspond to lognormal power. The coefficients must belong to that population and calibration procedure.

PLmed(d)=PL0+10nlog10(dd0)PLsample=PLmed+σZPrx,dBm=μσZ\begin{aligned}\mathrm{PL}_{\mathrm{med}}(d) &= \mathrm{PL}_{0} + 10n \log _{10}(\frac{d}{d_{0}}) \\ \mathrm{PL}_{\mathrm{sample}} &= \mathrm{PL}_{\mathrm{med}} + \sigma Z \\ P_{\mathrm{rx,dBm}} &= \mu - \sigma Z\end{aligned}d0=10 m; PL0=LFS(d0)=60.231104909 dB is assumed, not fitted. n=2.2, σ=5 dB and Z~N(0,1) are chosen fixture values. Positive Z increases loss.

At 100 m, median loss is 82.231104909 dB and μ=−73.938067181 dBm at R1-RX for state A. In dB, this Gaussian’s mean and median coincide. In watts, its arithmetic mean is the median power multiplied by exp[½(ln(10)σ/10)²]. The distinction matters whenever averages cross between linear and logarithmic units.

FP(p)=Φ ⁣(pμσ)q0.05=μ1.6448536269514722σoutage=Pr(P<Pthreshold)\begin{aligned}F_P(p)&=\Phi\!\left(\frac{p-\mu}{\sigma}\right)\\q_{0.05}&=\mu-1.6448536269514722\,\sigma\\\text{outage}&=\Pr(P<P_{\mathrm{threshold}})\end{aligned}For σ>0, Φ is the standard normal CDF. A 95% power-exceedance level is the lower 5th CDF percentile. A probability under an assumed model is not confidence in a field estimate.
Golden default · analytic distribution at R1-RX
StatisticValueConsequence
Median power / SINR−73.938067181 dBm / 15.648005968 dBMedian exceeds the hypothetical 8 dB SINR criterion.
Lower 5th percentile−82.162335316 dBmPower exceeded by 95%; below the −81.586073148 dBm threshold.
Upper 95th percentile−65.713799046 dBmThe favorable tail, not 95% coverage power.
Strict analytic outage6.305773693%Fails the conditional ≤5% outage target.
Primary 4096-draw outage6.567382813%Seeded finite-sample illustration; no field confidence interval.
Conditional received-power CDF at R1-RXSolid blue is the analytic distribution; dashed dark is the finite weighted sample. A vertical dotted line marks the required power. Higher CDF at the threshold means more outage. Exact values appear in the adjacent tables.ILLUSTRATIVE · F(P) = Pr(power ≤ P)0.000.250.500.751.00-102-90-78-65-53Threshold -81.59 dBm · strict outage 6.305774%Receive power P · dBm · R1-RXSolid: analytic · dashed: sample
Each curve is cumulative population mass, not a confidence band. Curves use a bounded display grid; tables retain exact analytic and weighted-sample summaries.
Common misconceptionAdding a fade margin guarantees a percentile.

A reserve becomes a percentile only through a validated distribution, population and dependency model. A scalar allowance by itself establishes none of them. Neighboring corridor samples may share the same obstruction; more closely spaced samples do not automatically provide more independent evidence.

Keep these quantities separate
QuantityWhat it represents / evidence needed
Median / intercept / slopeCentral scenario trend; fitted domain and holdout error needed.
Shadow variationLarge-scale variation across a named population; estimate residual distribution and correlation distance.
Fast fading / orientationDistinct mechanisms; neither is a hidden additional draw in this workbench.
Model-parameter uncertaintyLimited knowledge of n, σ, intercept and model form; quantify from calibration/validation.
Measurement and sample uncertaintyInstrument/calibration effects and finite effective sample count; not the displayed shadow spread.
Production reserve / deliberate marginChosen design allowances; not independent random variables without evidence.
Go deeperHow this sample can be reproduced exactly

p06-normal-samples-v1 uses nonzero xorshift32 state 0x1A2B3C4D, or alternate 0x6D2B79F5. Each draw applies s ^= s<<13; s ^= s>>>17; s ^= s<<5, then unsigned 32-bit conversion. u=(s+0.5)/2³² is strictly inside (0,1). Successive u1/u2 pairs produce √(−2 ln u1)cos(2πu2) first and the sine result second.

The first primary states are 3388403996, 3984204854, 2523572680 and 2838152257. N=1024 is the prefix of N=4096. An equal-weight empirical percentile is x[ceil(pN)−1], with p=0 choosing the minimum. CDF accumulates weighted mass; outage counts only powers strictly below threshold. Mixtures evaluate both states at every same Z with weight 1/(2N).

Analytic mixed quantiles use a bounded monotone solve with 10⁻⁸ dBm interval and 10⁻¹⁰ probability stopping tolerances. Zero σ uses exact step quantiles. An ideal 90° single-path linear-polarization null retains exact zero watts rather than a plotting floor.

Power variation alone does not describe how the channel changes a waveform. Delay and Doppler supply the next two scales.

08 / 10

Delay, Doppler, and coherence connect channel to waveform

Two channels deliver equal average power. Must they affect symbols equally?

Copies arriving at different delays can overlap differently within a symbol. Copies arriving from different directions at a moving receiver can also change relative phase over time. A power-only distribution contains neither a power-delay profile nor a Doppler spectrum.

τˉ=piτipiτrms=pi(τiτˉ)2pi\begin{aligned}\bar{\tau} &= \frac{\sum p_{i}\tau _{i}}{\sum p_{i} } \\ \tau _{\mathrm{rms}} &= \sqrt{\frac{\sum p_{i}(\tau _{i}-\bar{\tau})^{2}}{\sum p_{i}}}\end{aligned}τi are delays in seconds and pi are linear powers. Normalize by Σpi, not by the number of taps. The example uses delays 0/100 ns and normalized powers 0.8/0.2.
Independent channel-to-waveform scales · local illustrative examples
Quantity / conventionDerived valueWhat it does not establish
Mean excess delay20 nsNot RMS delay spread or a receiver timing offset estimate.
RMS delay spread40 nsNot the full 100 ns tap separation.
Reciprocal teaching scale 1/(5τrms)5.000000 MHzA heuristic scale; coherence needs a specified correlation measure and threshold.
Maximum Doppler magnitude v/λ at 3 m/s24.516960997 HzNot automatically the Doppler spread; path angles and motion directions matter.
Chosen reciprocal time scale 1/(2fD,max)20.394044762 msA convention-dependent comparison, not a guaranteed coherence time.
Portfolio symbol interval100 μs40 ns is 0.04% of this interval; the receiver’s tolerance still requires its waveform and processing.

Tse & Viswanath §§2.3.1–2.3.2 explain the reciprocal relationships and the dependence on definitions. Their significant-path delay extent is distinct from the RMS moment used above. Their time-scale convention uses Doppler spread and a different numerical factor; no universal equality is implied by our chosen 1/(2fD,max).

Goldsmith’s 2020 draft, §3.3.3, pp. 99–100, describes the 0.2/τrms approximation for a 0.5 correlation convention and explains why the factor depends on the profile and definition. Apply that qualification to our 5 MHz teaching scale.

Go deeperWhy 5 MHz is not an exact coherence boundary for this profile

Under uncorrelated taps, define normalized frequency correlation as R(Δf)=0.8+0.2e^(−j2πΔf·100 ns). Its magnitude at 5 MHz is 0.6, and 0.6 is its minimum. If “coherence bandwidth” means the first |R|=0.5 crossing, this two-tap profile has no such crossing. The often-used 1/(5τrms) estimate associated with a rough 50% correlation convention cannot be treated as that exact threshold here. The moment calculation is exact; the 5 MHz number is only a named reciprocal teaching scale.

For a single path, Doppler shift also depends on the cosine of its angle to velocity. If all significant paths have the same shift, a common frequency correction may remove it without fixing any multipath delay. Relative shifts drive time variation of the combined magnitude.

With many unresolved small paths and approximately independent uniform phases, a complex Gaussian channel can have a Rayleigh envelope. Adding a dominant specular component leads to a Rician alternative. For a separate unit-mean Rayleigh-power example, Pr(|h|²<0.1)=1−e⁻⁰·¹≈9.516258%. This is not the office shadowing distribution, and no such extra fading draw is applied by the workbench. Chapter 2 §2.4.2 states those mechanisms and assumptions.

The installed antenna can change which of those paths are strong. That makes orientation part of the scenario population, not a forgotten final margin.

09 / 10

Orientation, polarization, body, mounting, and diversity

Would the average of two orientations represent either one?

State A keeps the baseline broadside gain, aligned linear polarization and no pattern penalty. State B is a named local synthetic variant: 6 dB less directional pattern response plus ideal 45° linear misalignment. PLF=cos²45°=0.5 adds 3.010299957 dB loss. The total state change is 9.010299957 dB, but its probability weight must remain explicit.

Fmixture(p)=0.5FA(p)+0.5FB(p)F_{\mathrm{mixture}}(p) = 0.5F_{\mathrm{A}}(p) + 0.5F_{\mathrm{B}}(p)An equally weighted use population contains two complete state distributions. Apply each state’s own gain/polarization configuration before mixing probability.

Averaging component dB quantiles does not generally produce mixture quantiles. For our equal-weight, equal-σ Gaussian components the symmetry happens to put the mixture median halfway between the two component medians; the model still solves the CDF. That symmetry is not an algorithm for other weights, variances or tails.

Think about itSet σ to zero while retaining the 50/50 A/B mixture. Does every result become identical?
Answer

No. Each state collapses to one power, but the mixture retains two different point masses. Equality to the threshold is not outage. A custom 90° single-state polarization has exactly 0 W in this ideal model, with its full probability mass in outage for any positive signal threshold.

Common misconceptionOne antenna orientation represents the product.

Body proximity, mounting metal, cable attachment and rotation can change the pattern and polarization. A null in a required state should stay visible in the test matrix rather than being buried inside one arbitrary average margin.

The earlier 06.3 scalar integration model does not supply a complex channel or an installed vector pattern for this lesson. Nor do 06.4’s eight synthetic diversity samples calibrate our shadowing distribution. Carry the evidence identities forward, but do not silently promote one model’s illustrative outputs into another model’s field data.

Go deeperDiversity needs a joint distribution

Two antennas may offer different orientations or polarization responses, but a shared body shadow or blockage can affect both. Request joint signal, interference and noise behavior before computing selection or coherent-combining reliability. Marginal outage numbers alone cannot determine the benefit; neither can treating correlated margins as independent dB allowances.

We can now compare three complete conditional statements with the same ledger and receiver assumptions.

Ungraded review

Answer each question in your own words, then reveal the model answer.

  1. 01At fixed antenna gains and 2.450 GHz, what changes between 10 m and 100 m in free space?
    Model answer

    Free-space basic transmission loss rises exactly 20 dB, from 60.231104909 to 80.231104909 dB. With every other ledger term fixed, R1-RX power drops 20 dB, a factor of 100. Both points still need LOS, polarization and field-region validity; this scaling is not a range guarantee.

  2. 02A ledger subtracts mismatch and radiation efficiency after using directional realized gains. Repair it.
    Model answer

    Remove those extra deductions: the supplied realized gains already include antenna mismatch and dissipation at their real 50 Ω references. Keep the R1-to-R2 matched feed losses, the selected channel term, polarization factor and any separate declared orientation-pattern change once. R3 remains the decision boundary; noise/interference here are referred back to R1-RX.

  3. 03Can the office n=2.2 and σ=5 dB be used for a 60 GHz path through wet vegetation?
    Model answer

    Only as labelled algebraic extrapolation; calibration is unknown. The supplied local fixture applies over 10–1000 m at 2.450 GHz and has no field-derived coefficients. Vegetation, material, weather, polarization and antenna constraints require their own applicable evidence/models. An ITU catalogue scope is a routing aid, not a coefficient table or validation.

  4. 04Why can a farther two-ray point be stronger than a nearer one?
    Model answer

    The direct and reflected complex fields change relative phase with geometry. A farther point can leave a destructive-interference null. Sum fields before taking squared magnitude and replace the path term with the result. Γ=0 recovers Friis at the slant direct length rd. A nonmonotone curve cannot support an unqualified one-number range inversion.

  5. 05The office median clears the threshold by 7.648006 dB. Does it meet 95% exceedance?
    Model answer

    No. At R1-RX the lower 5th CDF percentile is −82.162335316 dBm, below the −81.586073148 dBm threshold. Strict analytic outage is 6.305773693%, above the allowed 5%. The seeded 6.567382813% sample outage is a finite illustrative estimate, not a confidence interval. With σ=0, equality meets the threshold; orientation mixtures can still contain multiple point masses.

  6. 06Write a complete conditional 100 m statement and the evidence needed before publishing a range specification.
    Model answer

    For the fictional 2.450 GHz office corridor at 100 m, state A, the stated real 50 Ω R1/R2 ledger, assumed PL0 at 10 m with n=2.2/σ=5 dB, and N/I=−100/−90 dBm over the same 1 MHz at R1-RX, the model predicts 93.694226307% of received powers at or above the threshold for an 8 dB R3 SINR screen. This is not 95% coverage and has no field confidence. Specify sites, mechanics, orientation weights, interferer modes, correlation/effective sample size, calibration/measurement uncertainty, holdout data and the eventual waveform criterion before assessing a product requirement.

References and further reading

Principles, models and access

Access/status checked 7 September 2026. Model link-distribution-workbench/2.0; fixture p06-m05-link-v1; sampler p06-normal-samples-v1; evidence snapshot p06-evidence-map-v1. All scenario coefficients, orientation penalties, receiver powers and criteria are deliberate teaching inputs. The Python oracle independently checks the fixture; it does not validate a physical product.

  1. ITU-R P.525-5, Calculation of free-space attenuation (11/2024). In force. Annex §§2.2–2.3, equations (3)–(6) actually read for flux, aperture and basic free-space loss. The implementation derives the MHz/km constant from exact c.
  2. ITU-R P.676-13, Attenuation by atmospheric gases and related effects (08/2022). In force. Scope and Annex 1 §1 read for atmospheric inputs and line-by-line model routing. No gas attenuation algorithm or coefficient table is implemented.
  3. Current ITU-R P-series catalogue. P.526-16 (11/2025), P.1238-13 (09/2025), P.2108-1 (09/2021) and P.838-3 (03/2005) official status pages checked. Catalogue scopes route diffraction, indoor, clutter and rain questions; their full normative models were not read or implemented.
  4. David Tse and Pramod Viswanath, Fundamentals of Wireless Communication, Cambridge University Press, 2005. Author-hosted Chapter 2, §§2.1.5–2.1.7, 2.3.1–2.3.2 and 2.4.2 actually read for ground reflection, shadowing, delay/Doppler and Rayleigh/Rician distinctions. Their order-of-magnitude conventions are distinguished from our RMS moments and local reciprocal scales.
  5. Andrea Goldsmith, Wireless Communications, draft of second edition, Chapters 1–7 (8 February 2020). Author-hosted draft, §3.3.3, pp. 99–100 read on 8 September 2026 for the profile-dependent 0.2/τrms correlation-bandwidth approximation. This draft identity is not a claim about the latest published edition.
  6. C. A. Balanis, Antenna Theory: Analysis and Design, 4th ed., Wiley, 2016. Official edition/contents verified. Friis, gain, aperture and polarization foundations are further reading; the full text was not accessed. No unseen book passage or clause is asserted as evidence.
  7. IEEE 145-2025, IEEE Standard for Definitions of Terms for Antennas. Official active status and public scope consulted; published 31 March 2026. The full normative text was not accessed; the local power and coordinate conventions are stated explicitly.